Different question jake is skipping stones onto a pond. each time he flings a stone in, he counts the number of times it skips over the water. the number of skips he recorded for each stone were 3, 2, 1, 3, 2, 5, 4, 1, 3, 3, 4, 1, 5, 4, and 2. which measure should jake use to calculate the difference of the highest and the lowest number of skips?

Range

Step-by-step explanation:

We are given the following data set for the number of skips every time Jake skipped a stone onto a pond:

3, 2, 1, 3, 2, 5, 4, 1, 3, 3, 4, 1, 5, 4, 2

It is a good idea to arrange the data set into ascending order just to be more clear about it:

1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5

Jake should find the range by calculating the difference of the highest and the lowest number of skips

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

answer: idk

step-by-step explanation: