b(1)=−7 b(n)=b(n−1)+12 find the 4th term in the sequence

4th term = 29

to generate the terms, substitute n = 2, 3, 4 into the rule

noting that b(1) = - 7

b(2) = b(2 - 1) + 12 = b(1) + 12 = -7 + 12 = 5

b(3) = b(3 - 1) + 12 = b(2) + 12 = 5 + 12 = 17

b(4) = b(4 - 1) + 12 = b(3) + 12 = 17 + 12 = 29

 The 4th term in the sequence is 29 .

Step-by-step explanation:

The given recursive formula for the sequence :

To find : 4th term

At n=2 , we have

  (Second term)

At n=3 , we have

 (Third term)

At n=4 , we have

 (Fourth term)

Therefore , the 4th term in the sequence is 29 .