5. factor the expression. 6x2 + 5x + 1 a)(3x + 1)(2x – 1) b)(3x – 1)(2x – 1) c)(3x – 1)(2x + 1) d)(3x + 1)(2x + 1)

The factored version of the equation 6x^2 + 5x + 1 is equal to (3x+1)(2x+1).

Step-by-step explanation:

Here is the reason why that equation is correct:

Use the FOIL method for each factored equation to see if it equals 6x^2 + 5x + 1.

(3x + 1)(2x - 1)

3x * 2x = 6x^2.

3x * -1 = -3x.

1 * 2x = 2x.

1 * -1 = -1.

6x^2 - x - 1.

(3x - 1)(2x - 1)

3x * 2x = 6x^2.

3x * -1 = -3x.

-1 * 2x = -2x.

-1 * -1 = 1.

6x^2 - 5x + 1.

(3x -  1)(2x + 1)

3x * 2x = 6x^2.

3x * 1 = 3x.

-1 * 2x = -2x.

-1 * 1 = -1.

6x^2 + x - 1.

(3x + 1)(2x + 1)

3x * 2x = 6x^2.

3x * 1 = 3x.

1 * 2x = 2x.

1 * 1 = 1.

6x^2 + 5x + 1.

D contains the only factored expression that equals 6x^2 + 5x + 1 as a result using the FOIL method.

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

answer: group b.

step-by-step explanation: