What is the area of a triangle whose sides are 10 meters, 14 meters, and 20 meters long? a.65 m2 b.100 m2 c. 70 m2 d.50 m2

Option A. 65 m^2

Solution:

Sides: a=10 m, b=14 m, c=20 m

Area: A=?

A=sqrt [p(p-a)(p-b)(p-c) ]

Semi-perimeter: p=(a+b+c)/2

p=(10 m+14 m+20 m)/2

p=(44 m)/2

p=22 m

A=sqrt [ (22 m)(22 m-10 m)(22 m-14 m)(22 m-20 m)]

A=sqrt [ (22 m)(12 m)(8 m)(2 m) ]

A=sqrt [ 4,224 m^4 ]

A=64.99230723 m^2

A=65 m^2

it should be a.

hope it

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !