Agame involving a pair of dice pays you $4 with probability 16/36, costs you $2 with probability 14/36, and costs you $6 with probability 6/36. what is your approximate probability of losing money in one play of the game?

0.56 or 56%

Step-by-step explanation:

Let x = winning amount in dollars, in a one play of the game.

there taxes values = -6, -2 and 4.

and P(x = -6) =

and P(x = -2) =

and P(x = 4) =

P (loosing money in one play of game) = P (x ≤ -2)

and P(x ≤ -2) = P ( x = -6) + P ( x = -2)

                    = + =          

                   = 0.555555556 ≈ 0.56

Probability of losing money in one play of the game is 0.56 or 56%

i can you with this question sweetie!

step-by-step explanation:

y + 11 = (1/4)(x + 16)

step-by-step explanation: