Answers: 1
![\bf AB\implies \begin{bmatrix} 4&-2&3\\2&0&5 \end{bmatrix}\cdot \begin{bmatrix} -1&-4&3\\3&5&-3\\0&2&-2 \end{bmatrix} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{lrlll} (4)(-1)+(-2)(3)+(3)(0)&=-10\\\\ (4)(-4)+(-2)(5)+(3)(2)&=-20\\\\ (4)(3)+(-2)(-3)+(3)(-2)&=12 \end{array}\impliedby \textit{the first row of the product} \\\\[-0.35em] \rule{34em}{0.25pt}](/tpl/images/0046/0417/ead1e.png)
![\bf \begin{array}{lrll} (2)(-1)+(0)(3)+(5)(0)&=-2\\\\ (2)(-4)+(0)(5)+(5)(2)&=2\\\\ (2)(3)+(0)(-3)+(5)(-2)&=-4 \end{array}\impliedby \textit{the second row of the product} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \begin{bmatrix} -10&-20&12\\-2&2&-4 \end{bmatrix}~\hfill](/tpl/images/0046/0417/d95b5.png)
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