Brandon earns a rebate each month on his meals and movie tickets. he earns $0.50 for each movie ticket and $2 for each meal. last month brandon purchased 22 movie tickets and earned $25. part a: create an equation that will determine the number of meals he purchased. (3 points) part b: solve this equation justifying each step with an algebraic property of equality. (6 points)

Let ticket be x and meal be y

So $0.50 for each movie ticket = 0.50x

$2 for each meal = 2y

He purchased 22 tickets, so x = 22

0.50 * 22 = $ 11

Now the total value is $25 (with both ticket and meal)

total = t

0.50x + 2y = t

you know x = 22 and t = 25

11 + 2y = 25

Part A)

2y = 25 -11

y = 14/2

y = 7

Number of meal is 7

Part B)

(don't know about part B)

0.50x + 2y = 25

0.50(22) + 2(7) = 25

11 + 14 = 25

25 = 25

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: