Calculate the resistance of a 270-cm length of copper wire with a 0.030-cm2 cross-sectional area. ( = 1.8 · 10-6 ohm-cm) r = ω 5.4 x 10-1 5.0 x 109 2.0 x 10-18 1.6 x 10-2

Given:-

The length of copper wire (L) = 270 cm

Area of cross-sectional (A) = 0.030

and specific resistance (ρ) = ohm-cm.

Use the formula  R=(Specific resistance*L)/A, to calculate the Resistance(R)

then, ohm

Simplify:

R = 0.0162 ohm = ohm

Therefore, the resistance of copper wire is,   Ω

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

what’s the question?