If the hypotenuse of a right triangle is 70 feet and one of the legs is 42 feet, what is the length of the other leg?

a^2 + b^2 = c^2

1)This can be seen as;

(side #1)^2 + (side #2)^2 = (hypotenuse)^2  

2)Now put the numbers;

(42)^2 + (side#2)^2 = (70)^2

3)Now square the numbers

1764 + (side#2)^2 = 4900

4)Now  we have to isolate the side we are trying to find, by subtracting 1764 from both sides

(side#2)^2 = 4900-1764

5)

(side#2)^2= 3136

6) Now we need to get rid of the square of side #2 (^2), to do this we have to do the opposite of a square, which is square rooting both sides.

√(side#2)^2 = √3136

7) Now the square and squareroot of of side#2 will cancel and the square root of 3136 is 56 if you plug it into your calculator

(side#2) = 56

Final Answer)

The length of the other leg is 56ft.

its a straight line parallel to the time axis