Find 3 consecutive odd integers such that twice the sum of the first and third exceeds the second by fifteen

The three consecutive odd integers are 3,5,7

How:

Let x, (x+2),(x+4) represent the three consecutive odd integers

Question states***  

2[x + (x+4)] = (x+2) + 15

solving for s

  4x + 8 = x + 17

    3x = 9

     x = 3   The three consecutive odd integers are 3,5,7

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2