What’s an equation of the line that is parallel to 3x+y=6 and passes through the point (-2,8)

We know that if two lines are Parallel then both the lines have same Slope.

Given : Equation of 1st Parallel line is 3x + y = 6

this can be written as :

y = -3x + 6

Comparing with standard form : y = mx + c

we can notice that slope = -3

We know that the form of line passing through point (x₀ , y₀) and having slope m is :

y - y₀ = m(x - x₀)

Here the 2nd Parallel line passes through the point (-2 , 8)

x₀ = -2 and y₀ = 8 and we found m = -3

⇒ y - 8 = -3(x + 2)

⇒ y - 8 = -3x - 6

⇒ -3x - y = -2

⇒ 3x + y = 2

im not sure

step-by-step explanation:

geometry: triangles

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lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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