Find three consecutive odd integers such that the first is 33 less than twice the second

n, n + 2, n + 4 - three consecutive odd integers

the first is 33 less than twice the second

n - 33 = 2(n + 2)       use distributive property

n - 33 = (2)(n) + (2)(2)

n - 33 = 2n + 4       add 33 to both sides

n = 2n + 37       subtract 2n from both sides

-n = 37      change the signs

n = 37

n + 2 = 37 + 2 = 39

n + 4 = 37 + 4 = 41

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it

a - base

b - exponent

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