Find three consecutive odd integers such that the first is 33 less than twice the second

the smallest integer will be x

2nd smallest will be x+2

largest will be x+4

therefore

2x+2-33=x

2x+2=x+33

2x=x+33-2

2x-x=33-2

x=31

the numbers will be 31,33 and 35

lets check whether it is correct

2x+2-33=x

31*2+2-33=31

62+2-33=31

64-33=31

31=31

therefore the answer 31,33 and 35 is correct

answer: the answer to this problem is yes because 4n + 4 does equal 2m - 6

step-by-step explanation: first you have to calculate 2m - 6 second you have to calculate 4n + 4 finally you have to get your answer

multiple allele inheritance is traits controlled by more than 2 alleles (ex: pigeons having 3 alleles of one gene govern their feather color).