Kyle and michael run a lap around a track. kyle gets a 50 meter head start and runs 3 meters per second. michael runs at a speed of 4 meters per second. how long will it take for michael to reach kyle

First, you need to put both equations in slope intercept form

Kyle: y=3x+50, because he runs 3 meters/second and he gets a 50 meter head start

Michael: y=4x

I think the answer would be 50 seconds

hope this helps

50 seconds

Step-by-step explanation:

Let x be the distance ( in meters ) from kyle to the point where they meet.

Since,

For kyle,

Distance = x,

Speed = 3 m/s

So, time taken by Kyle =

Now, for Michael,

Distance = (x + 50) ( Because Kyle is 50 meters ahead of Michael )

Speed = 4 m/s

So, time taken by Michael =

When they meet each other,

Hence, the time after which they meet = = 50 seconds

easy its decreasing

step-by-step explanation:

because its top point is at the to of the graph on the left side (atleast from the veiw i see it) now if that top point wast in the lower part of the graph it would be increasing hope this have a nice day

i believe so, according to my "strange" way of figuring out weird math problems like this.