It takes 12 hours for a single hose to fill a large vat. when a second hose is added, the vat can be filled in 4 hours. how many hours are required for the second hose working alone to fill the vat? enter your answer in the box.

Its 6 hours.

I should probably explain it, the reason for this is mainly just by dividing the fact that adding the other hose takes away 8 hours of work we can deduce that the amount of water it can put out can do it 2 times faster than the normal hose so the answer is 6

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v