What is the vertex of the equation, y= -3x^2+2x-7? a. (1/3, -20/3) b. (-1/3, -20/3) c. (-1/3, -19/3) d. (1/3, -19/3)

A

Given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then

The x-coordinate of the vertex is

= -

y = - 3x² + 2x - 7 is in standard form

with a = - 3, b = 2 and c = - 7, hence

= - =

Substitute this value into the equation for y-coordinate

y = - 3 ()² + 2 ( ) - 7

  = - + - = -

vertex = ( , - ) → A

practice. practice. practice.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet