Polygon a is similar to polygon b. the sides of a polygon a are three times larger than the corresponding sides of polygon b. the perimeter od polygon a is 144. what is the perimeter of polygon b ? a. 432 b. 12 c. 144 d. 48

Since similar polygons have proportional sides, their perimeters are proportional as well. Set up a ratio to find the

Side x of polygon A is to side y of polygon B as the perimeter of A is to the perimeter of B.

In mathematical terms:

x:y = A:B

We know that one side of A is 3 times as large as one side of B, so we can substitute x and y for those values:

3:1 = A:B

We also know that the perimeter of A is 144, so we can substitute that value as well.

3:1 = 144:B

Now we can use this proportion to find the perimeter of B. Multiply the means and extremes and solve:

3B = 144

B = 48

The perimeter of polygon B is 48.

I hope this helps =)

for the first question it would be the second answer for the second question it would be the third answer and for the third question it would be the first answer

step-by-step explanation:

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13