Use the graph below to answer the question that follows: trig graph with points at 0, 2 and pi over 2, 0 and pi, negative 2 and 3 pi over 2, 0 and 2 pi, 2 and 5 pi over 2, 0 and 3 pi, negative 2 what trigonometric function represents the graph? f(x) = −2 cos(x − pi over 2) f(x) = −2 sin(x − pi over 2) f(x) = 2 cos(x − pi over 2) f(x) = 2 sin(x − pi over 2)what trigonometric function represents the graph?   f(x) = −2 cos(x − pi/2)    f(x) = −2 sin(x − pi/2  )    f(x) = 2 cos(x − pi/2)    f(x) = 2 sin(x −pi/2 )

That would be  f(x) = -2sin(x - pi/2)

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh

the answer is d

for problems like this theres an app, its photomath that explains the problem and gives the answer hope i