What is the equation of the line that passes through (4,-1) and (-2,3)

First get slope

(4,-1) and (-2,3)

slope is

diff in y        4

=     = -2/3

diff in x       -6

use a point (-2, 3) and y - y1=M(x - x1)

y - 3= -2/3(x + 2)

y - 3= -2/3x - 4/3

 + 3              +3

    y = -2/3x - 4/3 + 9/3  (3 is 9/3)

     y = -2/3x + 5/3

5+2x=a

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