What is the solution set of x^2 - 10 = 30x

x^2-30x-10=0

Use the quadratic formula

-b +or- square root of b^2 -4ac all divided by 2a

a = 1       b = -30      c = -10

30 +or- square root of (30)^2-4(-10) all divided by 2

(30+sqrt940)/2

x=30.33

(30-sqrt940)/2

x=-0.33

The solution is x=-0.33 and 30.33

x^2-30x-10=0

Use the quadratic formula

-b +or- square root of b^2 -4ac all divided by 2a

a = 1       b = -30      c = -10

30 +or- square root of (30)^2-4(-10) all divided by 2

(30+sqrt940)/2

x=30.33

(30-sqrt940)/2

x=-0.33

The solution is x=-0.33 and 30.33

answer: howdy

step-by-step explanation:

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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