Can someone find the line of symmetry, vertex, roots, y-intercept and minimum or maximum for y=(x+3)^2-4 i need it now

The equation of the parabola is given is the Vertex Form. The general form of a quadratic equation in Vertex Form is:

So for our equation, and . Now let's solve the question.

1. Line of Symmetry:

Line of symmetry is given as , so our line of symmetry is .

2. Vertex:

Vertex is given as , so our vertex is .

3. Roots:

We find the roots by setting . Thus, we have

So,

and

So, solving these 2 equations we have

4. Y-Intercept:

To find y-intercept, we set . So we have

5. Minimum/Maximum:

A quadratic equation has minimum if is positive and maximum is is negative. Hence, this function has a minimum since is positive. The value of the minimum is . So for our question, the minimum is .

ANSWERS:

1. Line of Symmetry:

2. Vertex:

3. Roots:

4. y-intercept:

5. Minimum Value:

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb