Solve the following problems. given: ab ≅ bc and ae = 10 in, m∠fec = 90° m∠abc = 130°30' find: m∠ebc, ac

Because BA ≅ BC, we know the triangle is isosceles. Because ∠FEC=90°, we know BE is a median and angle bisector of ∠ABC.

Hence ...

... AC = 2×AE = 20 in

... ∠EBC = (1/2)×∠ABC = 65°15'

3x^3-2x^2+4x-3= -3

x^2+3x+3= 3

-3÷3= -1

x=-2

step-by-step explanation:

i began by flipping the problem to give me x= on the left (keeps it clearer for me).   so my problem simply became 10x-3=4x-6.  

1)   subtract 4x from the right side, which equals 0.   you do the same to the left of the equal as the right; therefore, subtract 4x from 10x, leaving 6x on the left.

              10x-3=4x-6   :   4x-4x on the right leaves only the -6        

2)             6x-3= 0-6 :    

                6x+3=   -6

3) divide