Blocks numbered 0 through 9 are placed in a box, and a box is randomly picked. the probability of picking an odd prime number is? the porbability of picking a number greater than 0 is that is also a perfect square is?

A) Since there are 3 (3,5,7) odd primes between 0-9 and there are 10 blocks from 0-9, the probability is 3/10

B)  Since there are 3 (1,4,9) perfect squares above 0 and there are a totally 10 blocks from 0-9, the probability is 3/10.

2 is the final ! : )

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.