The floor of a rectangular deck has a length that is 6 feet more than it’s width, x. hakeem is building the deck and decided to increase both dimensions by 3 feet. what is the new area, d, of the floor of the deck? a. x^2 + 12x + 27 b. x^2 + 9x + 18 c. x^2 + 9x d. x^2 +6x

Let the width of the rectangular deck be = x feet

The length is 6 feet more than the width so length is = x+6 feet

Let us assume that a total 3 feet is increased (1.5 feet on both ends)

As Hakeem decided to increase both dimensions by 3 feet, this means 1.5 feet is increased on both sides of the deck. So, length and width increases by 3 feet each.

Hence, new length is = x+6+3 = x+9 feet

New width is = x+3 feet

So new area = length*width

D =

=

= square feet

Hence, option A is correct.

£56

step-by-step explanation:

u divide 24 by 3 and u get 8 so if u do 8 time 7 or 8+8+8+8+8+8+8 u get 56 and 56 divided by 7 is 8.

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4