For what natural values of n is the difference (2−2n)−(5n−27) positive?

Positive numbers are numbers greater than 0

The value of natural values of n is the difference (2−2n)−(5n−27) positive is 4.14

Given:

(2 − 2n) − (5n − 27) > 0

open parenthesis

2 - 2n - 5n + 27 > 0

2 + 27 - 2n - 5n > 0

29 - 7n > 0

29 > 7n

divide both sides by 7

29/7 > n

4.1428571428571 > n

Therefore,

n < 4.14

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(2−2n)−(5n−27) >0

distribute

2-2n -5n +27 >0

combine like terms

-7n +29 >0

subtract 29 from each side

-7n> -29

divide by -7  (flips the inequality)

n < -29/-7

n <4.14

natural numbers are 1,2,3,4

n must be 1,2,3,4

1,2,3,4

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb