Arectangle and a square have the same area. the length of the rectangle is seventy feet more than two times its width. the length of a side of the square is thirty feet. which of the following equations would you solve for the dimensions of the rectangle? a) 30^2 = x(2x + 70) b) 30x^2 = 2x + 70 c) 302 = 70x * w mph d) 30 + 30 = 70 + x * 2 mph e) 30 * 2 = 70x^2 f) 100 = x^2 + x

The area of the square = 30^2  ft^2

area of the rectangle = x * (2x + 70) ft^2 (where x = the width)  and these areas are equal. Therefore:-

30^2 = x(2x + 70)

Its A

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

wth is with the little mtn top and what are you talking about like fix your words and accually make sence with them and i like was in a completly different question like three times like it seems like your ilitteret