Evaluate the expression 4ab + 5bc when a = 2, b = –6, and c = –2.

Answer          

Evaluate the expression

4ab + 5bc

when a = 2, b = –6, and c = –2.

To prove

As the expression given in the question be

4ab + 5bc

As given

a = 2, b = –6, and c = –2.

Put all the these values in the above expression.

= 4 × 2 × -6 + 5 × -6 × -2

= -48 + 60

=  12

Therefore the value of expression  4ab + 5bc  be 12 .

(when a = 2, b = –6, c = –2 be  -12)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.