Write the slope/intercept form of an equation of the like that's passes through the given point and is parallel to the graph of an equation (-2,-3) y=2x+1

The equation is y = 2x + 1

Step-by-step explanation:

First we have to find the slope of the line. In order to do so, solve the first equation for y. Since this is already solved for y, we can just pick the coefficient of x (2)

With the slope of 2, we now can plug the slope and point into point-slope form and get the final equation.

y - y1 = m(x - x1)

y - -3 = 2(x - -2)

y + 3 = 2x + 4

y = 2x + 1

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