Systems of equations substitution y=x-6 y=8x+1

y=x-6

subsitute x-6 for y in other equation

y=8x+1

x-6=8x+1

minus x from both sides

-6=7x+1

minus 1 both sides

-7=7x

divide by 7 both sides

-1=x

x=-1

subsitue back

y=x-6

y=-1-6

y=-7

x=-1 and y=-7 or in (x,y) form, (-1,-7)

ok

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)