Consider the given functions. f(x) = -5x^2 + 2x - 6 g(x) = -5x^2 -4x + 8 h(x) = 6x - 14 select the expression that will produce h(x). a. f(x) − g(x) b. f(x) + f(x) c. g(x) − f(x) d. f(x) + g(x) only one answer.

neat

in h(x) we notice that there are no x^2 terms,

we also notice that in f(x), the coeffent of the x^2 term is -5

in g(x), the coeffient of the x^2 term is also -5

in order to eliminate the x^2 terms, we must subtract one from another (since -5-(-5)=0), so the operation must be either f(x)-g(x) or g(x)-f(x)

we then can consider the constant term or the constant

if we look at the constant of h(x), we see that it is -14

in f(x) the constant is -6

in g(x) the constant is 8

we note that 14=-6-8, so g(x) must be multiplied by -1 then added to f(x)

ie f(x)-g(x)

if we check the linear term

in f(x), the linear term is 2x

in g(x) the linear term is -4x

if we do f(x)-g(x), the linear term will be 2x-(-4x)=2x+4x=6x which checks

the operation is f(x)-g(x)

answer is A