Two consecutive intergers have a sum of 93

"Consecutive" means an " unbroken or logical sequence ".

Let the first number be "x"

(x) + (x + 1) = 93

Simplify. Combine like terms

x + x + 1 = 93

2x + 1 = 93

Isolate the x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 1 from both sides

2x + 1 (-1) = 93 (-1)

2x = 93 - 1

2x = 92

Finally, to fully isolate the x, divide 2 from both sides

(2x)/2 = (92)/2

x = 92/2

x = 46

The first number is 46. Find the second. Plug in 46 for x

x + 1

(46) + 1`

47

Answers: 46, 47

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3 is greater then both of those numbers

9x