Afirework is shot into the air from an initial height of 6 feet. the height in feet of the firework above the ground is given by s(t)=-15t^2+52t+6, where t is time, in seconds, and t≥0, at what time will the firework be 45 feet off the ground?

Given function is

where t is the time in seconds and s(t) is the height of the firework in t seconds.

Given that height of the firework is 45 feet. Now we have to find when it happens that is find value of t when s(t)=45

Apply quadratic formula

or

or

or

Hence final answer is 2.3693 seconds and 1.09737 seconds.

Two answers means height of 45 feet will be attained two times.

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step-by-step explanation:

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