The length of the rectangle is twice its width. write and solve a system of linear equations to find the length l and width w of the rectangle (perimeter=36)i know that the width is 6 and the length is 12, i just need to know the 2 equations that prove that this is true

Here are the two equations for this problem:

Let length = L

Let width = W

Equation No. 1 -

L = 2W

Equation No. 2 -

2L + 2W = 36

First simply substitute the value of ( L ) from the first equation into the second equation to solve for ( W ) as displayed below:

Equation No. 2 -

2L + 2W = 36

2 ( 2W ) + 2W = 36

4W + 2W = 36

6W = 36

W = 36 / 6

W = 6

Now, we substitute the value of ( W ) from the second equation into the first equation to solve for ( L ) as displayed below:

Equation No. 1 -

L = 2W

L = 2 ( 6 )

L = 12

Therefore, L = 2W and 2L + 2W = 36 are the correct equations for this problem.

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Ithink the answer is a

The variables should add up to equal 1