The length of the rectangle is twice its width. write and solve a system of linear equations to find the length l and width w of the rectangle (perimeter=36)

1)  L = Length,  W = Width, perimeter = 36

then

2L+2W =36

L = 2W

of the equation 1 , find  W

2L+2W = 36⇒2L=36-2W⇒L= 36-2W/2⇒L= 18-W

Now substitute it value with the equation 2

18-W = 2W⇒18 =2W+W⇒18= 3W⇒W= 18/3 = 6, L = 18-6 = 12

NOW SUBSTITUTE THE VALUES IN THE EQUATION 1

2* 12+ 2*6 = 36 , IT IS FULFILLED

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

x=0

step-by-step explanation: