You want to make five - letter codes that use the letters a, f ,e ,r and m without repeating any letter. what is the probability that a randomly chosen code starts with m and ends with e? a) 0.01 b) 0.02 c) 0.05 d) 0.10

The correct answer option is C) 0.05

Step-by-step explanation:

We are given five different alphabets A, F ,E ,R and M and with the help of these, we want to make five letter codes without repeating ant letter.

Since, each letter can be used once so the probability of picking a M first = .

Now we want the following sequence:

(not E, not E, not E) = =

So the probability that a randomly chosen code starts with M and ends with E = =

50.6

step-by-step explanation:

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: