How is the data represented on a scatterplot that depicts an exponential model

points on a curvy line.

There are two mathematical laws that can be used to depict data represented on a scatterplot:

- linear law: y = m·x + b

- exponential law: y = kaˣ 

They have a few common characteristics: 

- they depend on parameters (m and k);

- they describe a direct proportionality;

The difference is that for a linear law it is constant the ratio between the increment on the y-values and the increment on the x-values, resulting in a straight line; on the contrary, for an exponential law it is constant the ratio between the value of the function at (x + 1) and the value of the function at x, therefore the ratio between the increments keeps increasing, resulting in a curvy line.Hence, if the data follow an exponential model, on a scatterplot the points would lie on a curvy line.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?