Rewrite the equation in vertex form. name the vertex and y intercept: y=3/5x^2+30x+382 could you also explain how to change to vertex form? it's the one thing im clueless about when it comes to quadratics

The vertex form is

To get vertex form , we apply completing the square method

For completing the square method we need x^2 alone

factor out 3/5 from first two terms

When we factor out 3/5, we multiply by 5/3

Now we take middle term divide by 2  and square it

50 divide by 2 = 25

25^2 = 625

Now we add and subtract 625

Take out -625 and multiply with 3/5  and add it with 382

Now factor x^2 + 50x+625 and write it in square form

We got vertex form

Vertex is (h,k)

From our equation , h=-25  and k =7

So vertex is (-25,7)

To find y intercept we plug in 0 for x in the original equation

y=382

So y intercept is (0,382)

do your own work and don"t cheat.

step-by-step explanation:

inverse operation of addition