Find 4 consecutive integers such that the sum of the first and the forth is 29

SOLUTION:

Let the first number of the four numbers = x

Therefore:

The fourth number of the four numbers = x + 3

x + x + 3 = 29

2x + 3 = 29

2x = 29 - 3

2x = 26

x = 26 / 2

x = 13

Number no. 1 = x = 13

Number no. 2 = x + 1 = 13 + 1 = 14

Number no. 3 = x + 2 = 13 + 2 = 15

Number no. 4 = x + 3 = 13 + 3 = 16

FINAL ANSWER:

Therefore, the four consecutive integers are 13, 14, 15 and 16.

Hope this helps! :)
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