Three married couples arrange themselves randomly in six consecutive seats in a row. find the probability that each woman will sit immediately to the left of her husband. the denominator of the probability fraction will be 6! = 720, the total number of ways to arrange six items.

1/120

The numerator of the probability fraction will be the number of ways to arrange 3 items: 3!  = 6. So the probability fraction is ...

... 6/720 = 1/120

The 3 items are the three married couples with the woman on the left.

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: