Solve the following system of linear equations. 3x − 5y = −39 6x + 2y = −42 select one: a. (-2, -14) b. (-8, 3) c. no solution d. infinitely many solutions

B

given the 2 equations

3x - 5y = - 39 → (1)

6x + 2y = - 42 → (2)

multiply (1) by - 2

- 6x + 10 y = 78 → (3)

add (2) and (3) term by term to eliminate x

(6x - 6x) + (2y + 10y ) = (- 42 + 78 )

12y = 36 ( divide both sides by 12 )

y = 3

substitute this value in either of the 2 equations and solve for x

(2) → 6x + 6 = - 42 ( subtract 6 from both sides )

6x = - 48 ( divide both sides by 6 )

x = - 8

solution is (- 8, 3 ) → B

the 3rd option is right

step-by-step explanation: