What is the solution to this system of linear equations? 2x 3y = 3. 7x-3y = 24 a.(2, 7) b.(3, –21) c.(3, –1) d.(9, 0)

I )2X+3Y = 3

II )7X-3Y = 24

of the equation ii  obtain X ,  7x-3y = 24⇒ 7X = 24+3Y⇒X = 24 +3Y/ 7

then substitute it value in equation I

2(24+3y)/7 + 3Y = 3

48/7+6y/7 +3y =  3

48+6y+21y =21

27y = 21-48

27y= -27

y = -1

substitute in any equation to obtain x

7x-3y = 24

7x-3(-1) = 24

7x = 24-3

7x = 21

x = 21/7 = 3

the option C ( 3,-1)

(8+64)^2= 5184 < answer

step-by-step explanation:

2^3 = 8

4^3= 64

(8+64)^2 = 5184