N^2=-35-12n how answer this question

n² = -35 - 12n  

Add 12n and 35 to both sides

n² + 12n + 35 = 0

Find the factors of 35 that add or subtract to positive 12:

Factors of 35: 1, 5, 7, 35

5 and 7 add up to 12

n² + 12n + 35 = 0

Instead of 12n, you can replace it with 7n + 5n because they add up to 12n

n² + 7n + 5n + 35

Factor the equation separately

n(n + 7) + 5(n + 7)

Now factor out the (n + 7)

(n + 7)(n + 5)

where r the answers

step-by-step explanation: