Find the maximum and minimum values of the given quadratic function: y = -x² + 2x +1 (-1 ≤ x ≤ 2)maximum value: at x =

we need more info to solve this

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x