Determine the intercepts of the line that correspond to the following table of values. -14,9 -10,18 -6,27

I'll need to assume that your "-14,9" means (-14,9); if so, please use parentheses next time to indicate that you're sharing the coordinates of a point.

As we go from (-14,9) to (-10,18), x increases by 4 and y increases by 9.  Thus, the slope of this line is m = rise / run = 9/4.

We want the intercepts of this line.  Let's use the slope-intercept form y = mx + b.  Substituting the given info:  -10 for x and 18 for y, and m = 9/4, we get:

18 = (9/4)(-10) + b, where b is the y-intercept.

Solving for b, we get 18 + 90/4 = (72+90)/4 = 162/4, or 81/2.

Then b = 81/2, and the equation of the line is y = (9/4)x + 81/2.

Now find the x-intercept.  To do this, let y = 0; then (9/4)x = -81/2,  Mult. both sides by 4 to eliminate the fractions:  9x = -162, or x = -18.  The x-intercept is (-18,0) and the y-intercept is (0,81/2)

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.