If you flip a fair coin 6 times, what is the probability that you will get exactly 2 tails?

Many events can't be predicted with total certainty. The best we can say is how likely they are to happen, using the idea of probability.

Tossing a Coin

When a coin is tossed, there are two possible outcomes:

heads (H) or

tails (T)

We say that the probability of the coin landing H is ½

And the probability of the coin landing T is ½

These are the basics. Now, back to your question,

 I like to think of these questions like they have spaces that can be occupied by heads or tails. In this case, the chance that tails occupies the first four spots is (1/2^4)(1/2)^2 where the first term is the chance of four tails in a row and the second is four heads in a row. Now this simplifies to 1/2^6 or 1/64. However, there is more than one way for 4 tails to appear. This we have to go back to our spaces that can be occupied. We desire 4 tails that we are choosing from 6 spaces. To do this, we apply the combinations formula nCr. Applying this, 6C4 equals (6!)/((2!)(4!)) = 15. Thus, our final answer is 15/64.

Source: Quora. com

https://www.mathsisfun.com/data/probability.html

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column

multiple all that

step-by-step explanation:

27×17