There are 21 animals on farmer cole’s farm — all sheep and chickens. if the animals have a total of 56 legs, how many of each type of animal lives on his farm? write a system of equations, and use the equal values method to solve it.

sheep usually have 4 legs each

chickens usually have 2 legs each

if c=number of shep and s=number of chickents, then c+s=21

total legs is 56, so 2c+4s=56

system of equations is c+s=21 and 2c+4s=56

equal values method? why do they have to keep changing names, it doesn't sound like subsitution so I'm assuming they mean linear combinations

c+s=21

2c+4s=56

multiply first equation by -2 and add to 2nd equation

-2c-2s=-42

2c+4s=56 +

0c+2s=14

2s=14

divide by 2

s=7

sub back

c+s=21

c+7=21

c=14

14 chickens and 7 sheep

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.