Find the equation of a line, in slope-intercept form of a line that passes through the point (9, 2) and is perpendicular to the line 2x - y = 8.

The equation of the line would be y = -1/2x + 13/2

Step-by-step explanation:

In order to get the slope of the line, you need to first find the slope of the original line. You do this by solving for y.

2x - y = 8

-y = -2x + 8

y = 2x - 8

Now that you have the slope, we take the opposite and reciprocal slope to be the perpendicular (based on the definition of perpendicular lines). This means we take the opposite of 2 (which is -2) and then we flip the term (which means -2 becomes -1/2).

To find the slope-intercept form, we'll use our new slope of -1/2 and a point in point-slope form and solve for y.

y - y1 = m(x - x1)

y - 2 = -1/2(x - 9)

y - 2 = -1/2x + 9/2

y = -1/2x + 13/2

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =