Argyle cut a 300-meter cable into two pieces. one piece was 15m longer than twice the length of the other. find the length of the longer piece.

205 m

let x be the length of one piece then the other piece is 2x + 15

The sum of the 2 pieces equals 300 m , hence

x + 2x + 15 = 300

3x + 15 = 300 ( subtract 15 from both sides )

3x = 285 ( divide both sides by 3 )

x = 95

length of longer piece = (2 × 95 ) + 15 = 190 + 15 = 205 m

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints

how am i supposed to answer

step-by-step explanation: