The ratio of hydrogen to oxygen atoms in water molecules is 2 to 1. if the beaker of water contained 4.1 moles of oxygen atoms, how many moles of hydrogen atoms did it contain? (note: a mole is a unit commonly used in chemistry. you don't need to know this to solve the problem, but in case you are interested, 1 mole=6.02 times 10^23 atoms) plz !

8.2

Step-by-step explanation:    

We have been given that the ratio of hydrogen to oxygen atoms in water molecules is 2 to 1.      

We can represent this information as:

Let x be amount of moles of hydrogen atoms in water beaker. The proportion of hydrogen and oxygen moles will be same in water beaker.

Upon substituting our values in above proportion we will get,

Therefore, the moles of hydrogen atoms in water beaker will be 8.2.

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)