Arectangle is 4 times as long as it is wide. if the length is increased by 4 inches and the width is decreased by 1 inch, the area will be 60 square inches. what were the dimensions of the original rectangle?

Let the Width of the Original Rectangle be : W

Given : Length of the Original Rectangle is 4 times as long as it's Width

⇒ Length of the Original Rectangle = 4 × W = 4W

Now Some Modifications are made, So that Original Rectangle becomes into a New Rectangle.

Given the Length of New Rectangle is 4 inches More than Length of Original Rectangle.

⇒ Length of New Rectangle = 4W + 4

Given the Width of New Rectangle is One Inch less than Width of Original Rectangle.

⇒ Width of New Rectangle = W - 1

We know that Area of a Rectangle is : Length × Width

Given the Area of New Rectangle is 60 inches²

⇒ (4W + 4)(W - 1) = 60

⇒ 4W² - 4W + 4W - 4 = 60

⇒ 4W² - 4 = 60

⇒ 4W² = 64

⇒ W² = 16

⇒ W = 4

Dimensions of Original Rectangle :

Length of Original Rectangle = 4W = 4 × 4 = 16 inches

Width of Original Rectangle = W = 4 inches

what is the question here

step-by-step explanation:

statement #3: proof- ang is congruent to ang ecd : angles are congruent.  

step-by-step explanation:

1: the missing angles in statement #3  

a.) acb  

reason- the reason why the answer is acb is because angle ecd and angle acb are both the same size *that's what the word congruent means this is really simple.  

2: the missing word in reason #3  

c.) vertical  

reason- the reason why the answer is vertical is because the angles in that diagram on figure 2 is slanted, which is vertical, and the e and a both lay on vertical lines. along with the other's, but e and a are the 2 main points you want to focus on. and c is kind of like your starting point, because c is for both angles, not just one.  

i hope that was and understanding.